AMC 12 Trigonometry: Square a Sum to Reveal a Double-Angle Value

A trigonometric problem may ask for a value that can be found without solving the angle. Look for an identity connecting the supplied expression directly to the requested one.

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Expand the given relationship

Suppose sinθ + cosθ = 1/2 for a real angle. Squaring gives sin2θ + cos2θ + 2sinθcosθ = 1/4.

The first two terms sum to 1, so 2sinθcosθ = -3/4. Therefore sin(2θ) = -3/4.

Check that the value is possible

The result lies between -1 and 1, as a sine value must. The original sum 1/2 also lies within its possible range from -√2 to √2.

These checks test plausibility; the identity provides the actual derivation.

Avoid claiming more than is given

The information does not automatically specify a unique angle or a unique sign for cos(2θ). Different angles can share the same given sum while differing in other expressions.

When solving for angles after squaring, return to the original unsquared condition to reject extraneous possibilities. This original example supports AMC 12 algebraic reasoning; current competition information should be checked through official MAA resources.

Continue reading: AMC 12 Trigonometry: Solve Equations Without Losing Solutions.

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Official information and further reading: Source 1

AMC 12 Vector Practice: Separate a Scalar Projection from a Vector

A projection may refer to a signed scalar component or a vector along a specified direction. Check which object the question requests before using a formula.

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Calculate the dot product

Let a = (3, 4) and b = (1, 2). Their dot product is 11, while b has squared length 5 and length √5.

The scalar projection of a along b is 11/√5. The vector projection is (11/5)b = (11/5, 22/5). The scalar alone does not contain the direction vector.

Check the perpendicular remainder

Subtract the projection from a to obtain (4/5, -2/5). Its dot product with b is 4/5 - 4/5 = 0, confirming that the residual is perpendicular to b.

The projection and residual add back to the original vector, providing a second check on the components.

Keep the direction vector nonzero

A projection onto the zero vector's direction is not defined by these formulas, because its length is zero and it has no direction. This is a condition, not a computational inconvenience to ignore.

This original exercise develops algebraic geometry reasoning for AMC 12 preparation, not an official topic prediction. Label scalar and vector answers clearly, and use MAA resources for current competition information.

Continue reading: AMC 12 Trigonometry: Solve Equations Without Losing Solutions.

Contact Hanlin

Planning a first attempt or reviewing a topic you find difficult? Scan the QR code and send AMC12 PROJECTION 1022. Include your school year, country or competition region, experience and the question you want to discuss.

Scan to contact Hanlin on WeChat. Send AMC12 PROJECTION 1022.

Contact Hanlin on WeChat

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Official information and further reading: Source 1

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